Find an nth-degree polynomial function with real coefficients satisfying the given conditionsIf you are using a graphing utility, use it to graph the function and verify the real zeros and the given function value n = 3 - 7 + 2i are zeros f(2) = 116

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

she gotta workk that a 2

step-by-step explanation:

b

step-by-step explanation:

u take $75 minus $60.the anwer/original($75)multiply by 100