In a litter of five puppies, what is the probability of getting two males and three females, assuming an even chance for
each gender?
1
(A) 32
(B) 0.031
1
(C) 16
5
(D) 16
(E) 4

The probability of getting two males and three females, assuming an even chance for  each gender is .

Given that,

Based on the above information, the calculation is as follows:

Here we use binomial probability:

Here n denotes the number of trials,

r denotes the number of successes,

p denotes the probability of success,

and q denotes the probability of failure (1−p).

Let's us assume the r be the number of male puppies.

Now  

n = 5, r = 2, p = 0.5, and q = 0.5.

So, put the values

So,  

=

Therefore we can conclude that the probability of getting two males and three females, assuming an even chance for  each gender is .

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5/16

Step-by-step explanation:

Use binomial probability:

P = nCr pʳ qⁿ⁻ʳ

where n is the number of trials,

r is the number of successes,

p is the probability of success,

and q is the probability of failure (1−p).

Let's say r is the number of male puppies.

n = 5, r = 2, p = 0.5, and q = 0.5.

P = ₅C₂ (0.5)² (0.5)³

P = 5/16

the range is 19

step-by-step explanation:

the range is biggest number minus the smallest, so in this case it would be

41 - 22 = 19

step-by-step explanation: