Assume lines p and q intersect to form adjacent angles 1 and 2. If m∠1=(7x+6)°
and m∠2=(8x−6)°,
find the value of x such that p is perpendicular to q.

x=12

Step-by-step explanation:

To make these 2 lines perpendicular to each other, one of their angles must be equal to 90 degrees.

Therefore, we can set up an equation with one of the angles:

7x+6=90

7x=84

x=12

The information of the other angle is useless in this case, but we can use it to check by plugging in 12 for x, and seeing if it equals to 90:

8*12-6=96-6=90

Therefore, x=12.

d? maybe

step-by-step explanation:

step-by-step explanation:

first, eliminate the parenthesis:

3

x

+

2

−

4

x

second, group like terms:

3

x

−

4

x

+

2

third, combine like terms:

(

3

−

4

)

x

+

2

→

−

1

x

+

2

→

−

x

+

2