at a basketball game at team made 58 successful shots they were a combination of one and two point shots the team scored 98 points in all right and solve a system of equations to find out the number of each type of shot

There were 18 1 point goals and 40 2 point goals

Step-by-step explanation:

Let the number of one point shots be x and the number of two point shots be y

Total number of shot is 58

x + y = 58 ••••(i)

Then;

Total of 1 point is 1 * x = x

Total of 2 points is 2 * y = 2y

x + 2y = 98 ••••••(ii)

x = 98-2y

Put this in 1

98-2y + y = 58

-y = 58-98

y = 40

x = 58-40

x = 18

b

step-by-step explanation:

a difference is the result of subtraction. while each of these expressions has subtraction in it, a difference will be the result when subtraction is the last operation applied in the order of operations for the expression. this means subtraction must be outside of the parenthesis. only b has this.

the answer is:

the answer is:

to solve the problem, we need to remember the quotient of power property, it's defined by the following relation:

if we have a quotienf of powers that have the same base, we need to keep the same base and subtract the exponent of the denominator power to the exponent of the numerator power.

so, we are given the expression:

then, calculating we have:

hence, the answer is:

have a nice day!