Need HELP RUNNING OUT OF TIMe :) Find the number.

the sum of the reversed number and the original number is 154. Find the original number, if the ones digit in it is 2 less than the tens digit.

86

Step-by-step explanation:

Let the number be 10x + y. So, the reversed number is 10y + x.

The sum is 154.

So, (10x + y) + (10y + x) = 154

⇒ 11x + 11y = 154

⇒ x + y = 14 (1)

Again, given that ones digit in the original number is 2 less than the tens digit.

So, y = x - 2 (2)

Now, solving (1) and (2) we get,

x + x -2 = 14

⇒ 2x = 16

⇒ x = 8

So, from equation (2), y = x - 2 = 8 - 2 = 6

Therefore, the original number is 10x + y = 10 × 8 + 6 = 86 (Answer)

i think is g(1)=-1.

hope that i can

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)