Ricardo has 2020 coins, some of which are pennies (1-cent coins) and the rest of which are nickels (5-cent coins). He has at least one penny and at least one nickel. What is the difference in cents between the greatest possible and least possible amounts of money that Ricardo can have?

The lowest amount would be (1 x 5) + (2019 x 1) = 2024 cents, or $20.24

The highest amount would be: (1 x 1) + (2019 x 5) = 10,096 cents, or $100.96

100.96 - 20.24 = 80.72

The difference in cents between the greatest possible and least possible amounts of money Ricardo can have is $80.72.

( pls)

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation:

the correct answer is 5 6 and 7