In a two-digit number, the units digit is 5 more that the tens digit. The number itself is three times the sum of its digits. What is the number?

27

Step-by-step

B = A + 5

10A + B = 3(A + B)

for your equations.

Let's replace the Bs in the bottom equation with A + 5s, because we know that's the same thing from the top equation.

10A + A + 5 = 3(A + A + 5)

11A + 5 = 3(2A + 5) careful when you distribute the 3 here

11A + 5 = 6A + 15

5A = 10

A = 2

Then we know that B is 5 more than that, so B = 7.

Your number is 27.

We double check this and see that the 7 is five more than the 2. 27 is three times what we get when we add the digits (2 + 7 = 9).

answer

the correct answer is

explanation

the given function is

the excluded values are obtained by solving:

we factor to obtain:

the excluded values are

answer: my brother can figure it out, imma go get him so i can answer : ) edit: my brother is sleeping, sorry man

step-by-step explanation: