A population of geese doubles every 18 months. If there are 5 geese initially, how many years will it take for there to be 111 geese?

7 years

Step-by-step explanation:

Let t be the number of periods in which geese doubles .

The exponential growth function: , where A = initial value , b= growth factor.

As per given , A = 5 , b=2

i.e. Number of geese after t periods =

Put y=111, we get

Taking log on both sides , we get

Now , total months = 4.47 x 18 =80.46≈ 80 months

since 1 year =12 months

Number of years it will take

Hence, it will take 7 years (approx.)

the equivalent expression are always the hardest ones but you look at the gcf also

step-by-step explanation: