If the graph of the function f has a multiple zero at x = 2, what is a possible exponent of the factor x - 2? Justify your reasoning.

The exponent is 2.

Step-by-step explanation:

Remember multiplicity rules:

At x=2, we have the factor (x-2).

From the graph, we can see that the graph bounces off at that point.

Hence, the multiplicity of (x-2) must be even.

Therefore, a possible exponent for the factor (x-2) is 2. Any even number will suffice.

the correct answer is x/3+10≥32

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