This is the question can someone help

The coordinates of the vertices of triangle Q'R'S' will be:

Step-by-step explanation:

Given the coordinates of the vertices QRS

The coordinates of the vertex Q is (-2, 3)

The coordinates of the vertex R is (-5, -3)

The coordinates of the vertex Q is (2, -4)

As we know the rules of translation that:

If you move horizontally 'c' units to the left, then 'c' units are subtracted to the x-coordinate of each of the vertices.

if you move 'c' units up, then 'c' units are added to the y-coordinate of each of the vertices.

Translation 6 units up and 4 units to the left.

(x, y) → (x - 4, y + 6)

As the triangle Q'R'S' is the image of the triangle QRS translated 6 units up and 4 units to the left.

So,

the coordinates of Q' will be:

(x, y) → (x - 4, y + 6) = (x, y) → (-2 - 4, 3 + 6) = (-6, 9)

the coordinates of R' will be:

(x, y) → (x - 4, y + 6) = (x, y) → (-5 - 4, -3 + 6) = (-9, 3)

the coordinates of S' will be:

(x, y) → (x - 4, y + 6) = (x, y) → (2 - 4, -4 + 6) = (-2, 2)

Therefore, the coordinates of the vertices of triangle Q'R'S' will be:

300

step-by-step explanation:

28-600w < 300

28-600w > 300

600-28w < 300

600-28w > 300