Find three consecutive odd integers such that the sum of the smallest number and twice the middle number is 10 more than the largest number.

The three consecutive odd numbers are 5 , 7 , and 9 .

Step-by-step explanation:

Let the three consecutive odd integers be x, x+2 , x+4

Smallest number = x

Middle number = x+2

Largest number = x+4

As per given,

(Smallest number )+ 2 (Middle number ) = 10 + (Largest number)

Hence, Smallest number = 5

Middle number = 5+2 = 7

Largest number = 5+4 =9

hence, the three consecutive odd numbers are 5 , 7 , and 9 .

a negative exponent is translated as follows:

so, we have

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: