If a is positive and c is negative, how many real-number solutions will the equation ax^2+bx+c=0 have? Explain. !!, Please help me!

If a is positive and c is negative, there will be 2 real numbers solutions

Step-by-step explanation:

To get this, we need to get the value of the discriminant

Mathematically;

D = b^2 - 4ac

In this case , since a is positive and c is negative;

Then b^2 - 4ac will be positive

Thus b^2 - 4ac will be greater than zero

If the discriminant D is greater than zero, then we should expect 2 real-number solutions

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step-by-step explanation: