According to a survey, 10% of Americans are afraid to fly. Suppose 1100 Americans are sampled. a) What is the probability that 121 or more americans in the survey are afraid to fly

The probability that 121 or more Americans in the survey are afraid to fly is 0.1335.

Step-by-step explanation:

Let X denote the number of Americans afraid to fly.

The proportion of Americans afraid to fly is, p = 0.10/

A random sample of n = 1100 Americans are selected.

The random variable X follows a Binomial distribution with parameters n = 1100 and p = 0.10.

But the sample selected is too large and the probability of success is close to 0.50.

So a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

1.np ≥ 10

2.n(1 - p) ≥ 10

Check the conditions as follows:

Thus, a Normal approximation to binomial can be applied.

So,  

Compute the probability that 121 or more Americans in the survey are afraid to fly as follows:

Thus, the probability that 121 or more Americans in the survey are afraid to fly is 0.1335.

answer: a

step-by-step explanation:

if xy ~ yz therefore xy would be the same length as yz

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step-by-step explanation: