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If -3/2 and 5 are solutions, what is the value of a, b, and c? (ax+b)(x+c)=0

Step-by-step explanation:

If -3/2 and 5 are solutions to the quadratic equation, hence the expression will give;

(x-(-3/2))(x-5) = 0

(x+3/2)(x-5) = 0

Compare the resulting expression with (ax+b)(x+c)=0, we can see that;

ax = x

divide both sides by x

ax/x = x/x

a = 1

b = 3/2

-5 = +c

c = -5

Hence a = 1,  = 3/2 and c = -5

the barter

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