The store at which Andy usually shops is having a sale. Roast beef costs $4 per pound and shrimp costs $10 per pound. Let x = pounds of roast beef and y = pounds of shrimp

Write an inequality to represent the different possible combinations that Andy can buy if he has $96.

What is one possible combination of roast beef and shrimp that Andy can buy?

Part 1;

10y + 4x ≤ 96

Part 2;

y = 8

x = 4

Step-by-step explanation:

1 - Write an equation

Let z equal the total price

10y + 4x = z

2 - Use that to answer the questions

"Write an inequality to represent the different possible combinations that Andy can buy if he has $96."

If Andy has $96 that means the amount the two add up two can equal 96 or be less than 96 however not any more. That means 10y + 4x must be less than or equal to 96. This is written as follows

10y + 4x ≤ 96

With this in mind we can answer the following question of what is one possible combination. To do this, lets assume

10y + 4x must equal 96

Lets make 96 divisible by 10 using our pounds of roast beef.

To do this we need to get rid of the 6; which we can do so by turning 4x into 16. 4 goes into 16 4 times.

Therefore;

10y + 4x = 96

10y + 4(4) = 96

10y + 16 = 96

      - 16   - 16

10y= 80

Divide both sides by 10

y = 8

And our x when y = 8 was 4

so

x = 4

3.how is solving radical equations different than solving linear equations?

step-by-step explanation:

dude thats to long figure it

step-by-step explanation: