A university with a high water bill is interested in estimating the mean amount of time that students spend in the shower each day. In a sample of 11 students, the average time was 4.94 minutes and the standard deviation was 1.27 minutes. Using this sample information, construct a 99% confidence interval for the mean amount of time that students spend in the shower each day. Assume normality. a. What is the lower limit of the 99% interval? Give your answer to three decimal places.
b. What is the upper limit of the 99% interval? Give your answer to three decimal places.

i used to know how to do this in 7th but i forget easily

step-by-step explanation:

step-by-step explanation:

if you want to solve percent error follow these steps.

1. subtract the accepted value from the experimental value.

2. take the absolute value of step 1.

3. divide that answer by the accepted value.

4. multiply that answer by 100 and add the % symbol to express the answer as a percentage.

if you want to solve percent of change just do this.

1. work out the difference (increase) between the two numbers you are comparing.

2. divide the increase by the original number and multiply the answer by 100. if your answer is a negative number then this is a percentage decrease.

hope this : )

3 qrs + 3/2 xy hope this : /

step-by-step explanation:

~dasgupta/mathbook/append17dec2k8.pdf