64 - (16/3)= 208/3 I need help understanding HOW the answer to this is 208/3. Please give an explanation ASAP!!

64 - (-16/3) = 208/3

Step-by-step explanation:

I think the problem may be written incorrectly. For this to be correct, it must be 64- (-16/3) = 208/3.

To get 203/3 you have to find a common denominator because in order to subtract (or add) fractions, they must have the same denominator.

However, 64 does not have the same denominator as -16/3!!

We can write 64 as 64/1, and to give it the same denominator as -16/3, we need to multiply the denominator by 3

BUT we have to do the same thing to the numerator!!! We can't only change the denominator. If one changes, the other has to change too.

So lets multiply the numerator and denominator by 3. 64 x 3 = 192

1 x 3 = 3

Now we have 192/3

Subtracting a negative number is the same as adding. So instead we can write 192/3 + 16/3

Add 192 and 16 to get 208, so now you have 208/3

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2