Two numbers have prime factorizations of 2^2 · 3 · 5 and 2 · 3^2 · 7. Which expression can be used to find their least common multiple?

23 · 33 · 5 · 7
2 · 3
2^2 · 3^2
6 · 2 · 3 · 5 · 7

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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the answer is 11.2 (i know i’m late)

the answer is a.

135 and 80

step-by-step explanation:

v=1788.75

step-by-step explanation:

i belive that is the answer