Find three consecutive odd integers such that the sum of the smallest number and twice the middle number is 10 more than the largest number.

As the first number is 5, the second will be 7, and the third will be 9.

Step-by-step explanation:

First, let's break down what the information is telling us.

"three consecutive odd integers" means each number is 2 away from each other. So if we were to assign the variable x as the first number, the second would be x + 2 and the third would be x + 4

"sum of the smallest number and twice the middle number" refers to adding the first number and 2 times the second number. So we would write:

x + 2(x + 2)

"is 10 more than the largest number" connects the second part to an equation. This is saying the third number plus 10. So for this, we would write:

(x + 4) + 10

Now we join the information that we have written mathematically into an equation. Since we have an equation, we can solve for the first number, and hence the second and third numbers.

x + 2(x + 2) = (x + 4) + 10

x + 2x + 4 = x + 14

3x + 4 = x + 14

2x = 10

x = 5

As the first number is 5, the second will be 7, and the third will be 9.

The key idea for solving this question is to define a variable and connect it to an equation using the information provided. Try to think about how much information is needed and how many variables need to be defined.

the answer is (4,3)

since the rule for r0, 90º is (-y,x) and it was already applied to form the image, all you have to do is reverse the answer using this formula.

c.   x=2.4cm

step-by-step explanation:

similar triangles are triangles which have the same shape but not the same size. this means their angle measures are equal but their side lengths are not instead they are proportional. to solve, we will set up a proportion and solve.

a proportion is two equal ratios set equal to each other. we form the ratios by finding corresponding sides (sides which match to each other on both triangles by their position). out ratios will be one side of the small triangle over the corresponding side on the big triangle as shown below:

.

to solve the proportion, we'll cross multiply by multiplying numerator with denominator across the equal sign.