A piece of cardboard has the dimensions (x + 15) inches by (x) inches with the area of 60 in 2 . Write the quadratic equation that represents this and show your work. Then find the possible value(s) for x, and find the actual dimensions of the postcard.

The actual dimension is 18.28 by 3.28

Step-by-step explanation:

Given

Dimension:

Required

Determine the quadratic equation and get the possible values of x

Solving (a): Quadratic Equation.

The cardboard is rectangular in shape.

Hence, Area is calculated as thus:

Open Bracket

Subtract 60 from both sides

Hence, the above represents the quadratic equation

Solving (b): The actual dimension

First, we need to solve for x

This can be solved using quadratic formula:

Where

So:

Split:

or

or

or

But length can't be negative;

So:

The actual dimensions: is

The actual dimension is 18.28 by 3.28

2 x^2 -3x+p

sum of roots = 3/2

let other root be x

3+ x = 3/2

x= 3/2 - 3 = -3/2

product of roots = p/2

3× -3/2 = p/2

-9 = p

⭐⭐

-7

step-by-step explanation:

x^2 + 18x + 74 = (x + 9)^2 - 81 + 74

= (x + 9)^2 - 7.

so q = -7.