100PTS AND BRAINLIEST PLEASE HELP Reflect ΔECD over segment AC. This establishes that _. Then, translate point E' to point A. This establishes that _. Therefore, ΔACB ~ ΔECD by the AA similarity postulate.

a- ∠ABC ≅ ∠E'D'C'; ∠E'D'C' ≅ ∠ABC
b- ∠ACB ≅ ∠E'C'D'; ∠D'E'C' ≅ ∠BAC
c- ∠ACB ≅ ∠E'C'D'; ∠E'D'C' ≅ ∠ABC
d- ∠ABC ≅ ∠E'D'C'; ∠D'E'C' ≅ ∠BAC

b- ∠ACB ≅ ∠E'C'D'; ∠D'E'C' ≅ ∠BAC

Step-by-step explanation:

I got it right on the test :))

b- ∠ACB ≅ ∠E'C'D'; ∠D'E'C' ≅ ∠BAC

Step-by-step explanation:

Correct On test !!

the slope of the line is 60

one point on the line is (40,10)

step-by-step explanation:

in the equation outside the parenthesis the equation always tells you the slope. in this case it is 60.

in the parenthesis is also says 40 which is x because it is near the x and 10 is y because it is near y.

b

step-by-step explanation: