Pls pls help asap pls

Step-by-step explanation:

3y+7=2x

3y=2x-7

y=(2/3)x-7/3

when parallel, the y=ax+b, the a keeps the same

so it‘s y=(2/3)x-a

and it pass (2,6), so 6=(2/3)*2 -a

6=4/3-a

-a=(18-4)/3

-a=14/3

a=-14/3

f(2x−x2)=−3x2+6x−1

step-by-step explanation:

set up the composite function and evaluate.

f(2x−x2)=−3x2+6x−1