Girl please help how do you graph y= 3x + 2

The equation is in the form of y = mx + b which make it really easy to graph.

m = the slope  

b = the y-intercept

You can make the first point at the y-intercept.

Where x = 0 and y = 2, or plot the point ( 0, 2 ).

Next we use the slope to start plotting new points.

The slope is 3 which, in rise over run form, is . Since 3 is positive we go up 3 units from the y-intercept and 1 to the right because it's positive. This makes a point at ( 1, 5 ). Then from that point go up 3 and 1 to the right again to get ( 2, 8 ).

We can continue using the slope to plot more points and then draw a continuous line through them to finish graphing the linear function.

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0

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step-by-step explanation: