Suppose a box contains 3 defective light bulbs and 9 good bulbs. Three bulbs are chosen from the box without replacement. What is the probability that at least one of the bulbs drawn is defective?

1/4

Step-by-step explanation:

3+9=12

12/3=4

step-by-step explanation:

no of data

divide by no of mode

+25 = x

step-by-step explanation:

here x is the hypotenuse of a right triangle whose legs are 7 and 24.   by the pythagorean theorem, 7² + 24² must equal x²:

x² = 49 + 576 = 625.   thus, x = +√625 = +25 = x