Brian uses a linear regression to model the relationship between cricket chirp rate and temperature shown in the table.
Chirp Rate
(chirps/sec)
20
16.2
18.4
15
17
Temperature
(OF)
88.6
83.3
84.3
79.6
83.5
Using the model, he finds the predicted temperature for a chirp rate of 19 chirps per
second to be

100 points, hi, i’m not sure what to do here,the data doesn’t seem to be quadratic .? can anyone me, in advance

For [tex]f(x) = 4x + 1[/tex] and (x) = [tex]g(x)= x^{2} -5,[/tex] find [tex](\frac{g}{f}) (x)[/tex]a. [tex]\frac{x^{2} - 5 }{4x +1 },x[/tex] ≠ [tex]-\frac{1}{4}[/tex]b. x[tex]\frac{4 x +1 }{x^{2} - 5}, x[/tex] ≠ ± [tex]\sqrt[]{5}[/tex]c. [tex]\frac{4x +1}{x^{2} -5}[/tex]d.[tex]\frac{x^{2} -5 }{4x + 1}[/tex]

Determine domain and range, largest open interval, and intervals which function is continuous.