The figure below shows rectangle ABCD: Rectangle ABCD with diagonals AC and BD passing through point E

The following two-column proof with missing statement proves that the diagonals of the rectangle bisect each other:

Statement Reason

ABCD is a rectangle. Given

Line segment AB and Line segment CD are parallel Definition of a Parallelogram

Line segment AD and Line segment BC are parallel Definition of a Parallelogram

Alternate interior angles theorem

Line segment BC is congruent to line segment AD Definition of a Parallelogram

∠ADB ≅∠CBD Alternate interior angles theorem

ΔADE ≅ ΔCBE Angle-Side-Angle (ASA) Postulate

Line segment BE is congruent to line segment DE CPCTC

Line segment AE is congruent to line segment CE CPCTC

Line segment AC bisects Line segment BD Definition of a bisector

Which statement can be used to fill in the blank space?

  5.   y=6; de=7; fg=8

  6.   x=4.2; jl=14.2; mn=13

step-by-step explanation:

when chords cross inside a circle, the product of the segment lengths is a constant.

5. dh×eh = fh×gh

  y = gh = dh×eh/fh = 3×4/2 . . . divide by the coefficient of gh

  y = 6

of course, the total chord length is the sum of the lengths of its segments.

  de = dh +eh = 3+4 = 7

  fg = fh +gh = 2+6 = 8

6. this problem works the same way as the previous one.

  x = lk = mk×nk/jk = 6×7/10 = 4.2

  jl = jk +lk = 10 +4.2 = 14.2

  mn = mk +nk = 6 +7 = 13

comment on chords and secants

you can think of the points h (problem 5) and k (problem 6) as points where the chords meet. a chord is part of a secant line, a line that intersects the circle in two points. one can also consider these points (h or k) to be the points where the respective secant lines meet.

then, the product that is a constant is the product of the distance from the meeting point (h or k) to one circle intersection with the distance from that meeting point to the other circle intersection. for problem 5, the constant is the product hd×he = hf×hg.

it turns out that this rule regarding the products of lengths to points of intersection is also true when the secants intersect outside the circle.

that is, you only need to remember one rule to work both kinds of problems.

the answer to your question a or b but i am pretty sure it is b. i hope this : )

step-by-step explanation:

answer: 298143

step-by-step explanation:

students group

step-by-step explanation:

a person who   joins a party or a seminar can explain his feelings about that particular occasion better more than anyone else.

as bella managed a show for the students in the school and invited students to watch that show

hence

students group will be the best group to survey to find this information