Starting with 54 and 36, replace the 54 with the greatest common divisor of 54 and 36, obtaining a1, and then replace 36 with the least common multiple of 54 and 36, obtaining b1. Repeat the procedure on a1 and b1, obtaining a2 and b2 and so on. Starting with a1 and b1, what is the least number of times this procedure can be repeated until a1 and b1 are obtained again?

1 time

Step-by-step explanation:

Given numbers are 54 and 36.

The greatest common divisor of 54 and 36 = 18

So, .

The least common multiple of 54 and 36 = 108

So, .

As 54 is replaced by and 36 is replaced by , so after applying the given procedure, the new number is

Now, apply the same procedure, to get and .

The greatest common divisor of 18 and 108 = 18

So, .

The least common multiple of 18 and 108 = 108

So, .

As is replaced by and is replaced by , so after applying the given procedure, the new number is

which is the same as in equation (i)

Hence, after applying the procedure 1 time after , the obtained number is the same as .

answdf

step-by-step explanation: bcuz d is right

3. (5x + 1) - (-10x + 6)

simplify the answer choice. combine like terms. remember to distribute the negative to the terms inside the second parenthesis. also remember that two negatives = one positive, and one of each sign = negative.

- (-10x + 6) = + 10x - 6

simplify. combine like terms:

5x + 1 + 10x - 6

5x + 10x + 1 - 6

15x - 5

∴ it is your answer

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