Given g(x) = 2x + 3, solve for when g(x) = 3.
HELP PLEASE ITS A TEST HELP A TEEN OUT!!

g(x)=2x+3

g(x)=3

use the substitution for g(x)

g(3)=2(3)+3

do the parenthesis first because of PEMDAS

P= parenthesis

E= exponents

M= multiplication

D=  division

A= addition

S= subtraction

g(3)=2(3)+3

g(3)=6+3

g(3)=9

g(3)=9

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i