Suppose that when a skunk sprays, the odor has a half-life stink potency of 8 hours. This means that the skunks spray would have a stink odor of 100%
when it is first sprayed. Then, after 8 hours, it would smell half as bad (and
be at 50% of its potency). What percent potency would still exist after 1
day? Explain/show your work.

12.5% Potency

Step-by-step explanation:

8 x 3 = 24 hours in 1 day so 3 half lifes would progress in 24 hours.

100% Hour 0 Spray (Half Life 0)

50% Hour 8 Spray (Half Life 1)

25% Hour 16 Spray (Half Life 2)

12.5% Hour 24 Spray (Half Life 3)

hello :

by applying the distributive property :

6 × 4.3 = 6 × ( 4 + 0.3 )

            =   (6 ×   4) + (6 ×   0.3)

            = 24 + 1.8

6 × 4.3 = 25.8

sorry i got nothing

step-by-step explanation: