Many people think that a national lobby's successful fight against gun control legislation is reflecting the will of a minority of Americans. A previous random sample of 4000 citizens yielded 2250 who are in favor of gun control legislation. How many citizens would need to be sampled if a 90% confidence interval was desired to estimate the true proportion to within 4%?

416

Step-by-step explanation:

Given that:

A previous random sample = 4000

Sample mean = 2250

The confidence interval level = 90%

Desired Margin of error E = 0.04

The level of significance at 90% C.I  = 1 - 0.90 = 0.10

The critical value

  ( From the  z tables)

n = 416.21

Thus, the number of citizens required to be sampled is 416

a. 12.5 kg

step-by-step explanation:

f = ma

so

m = f/a = (2500 n)/(200 m/s²) = 12.5 kg

1 n = 1 kg·m/s²

they used 313 gallons of paint