The mean June midday temperature in Desertville is 36°C and the standard deviation is 3°C. Assuming this data is normally distributed, how many days in June would you expect the midday temperature to be between 39°C and 42°C?

The value is  

Step-by-step explanation:

From the question we are told that

   The mean is  

    The standard deviation

Generally the probability that in June , the midday  temperature is between  

39°C and 42°C is mathematically represented as

=>  

From the z table  the area under the normal curve to the left corresponding to  1 and  2  is

     P(Z   < 2)  = 0.97725

and

    P(Z   < 1)  = 0.84134

=>  

Generally number of days in June would you expect the midday temperature to be between 39°C and 42°C

Here n is the number of days in June which is  n = 30

=>    

20%

step-by-step explanation:

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.