A university wants to build a new residence hall with dorm rooms. The length is 3x+1 ft and the width is x^2-1 ft. If the university wants each room to have 195ft^2 of living space, what should be the dimensions of each dorm room? ["living space confuses me because idk if it's volume or bottom surface area]

Length of room, l = 3x + 1 ft.

Breadth of room, b = x² -1 ft.

Now, it is given that university wants each room to have 195 ft² of living space.

So,

So, above equation has two complex root and one real root i.e x = 4.08 ft .

Therefore, Length of room is 13.24 ft and breadth is 15.65 ft.

Hence, this is the required solution.

47 - 90 = 43

43 - 180 = x

x = 137

b. y = 4x - 2

step-by-step explanation:

to find a parallel equation to an equation, make sure both equations have the same slope but different y-intercepts.

y = 4x + 1

4 = slope

1 = y-intercept

y = 4x - 2

4 = slope

-2 = y-intercept

they both have the same slope but different y-intercepts, so, b. is the correct answer.

and to check your work, you can graph both equations. : )