Taking into account identical letters, how many ways can the researcher arrange the word CALLITRICHIDAE that start or end with vowels?

241,920 different ways

Step-by-step explanation:

We have 6 vowels, but A repeats twice and I repeats three times, so the number of ways in which each can either start or end the word:

³P₂ = 3! / (3 - 2)! = 6 / 1 = 6 ways

You can start words with A, E or I, or end the words with A, E, or I.

the remaining 8 consonants can be arranged in 8! ways = 40,320 ways

total number of ways that the letters can be arranged = 6 x 40,320 = 241,920 different ways

f(x) has value 150 at x= 0

and 0 at x= 3

so d(f(x))/dt = slope = -150/3 = -50

ok so the answer to your question is simple as long as you look at the different dimensions that contain the exemplary letters that combined in the right order give you words that eventually within the 5th dimension will conform and give you the correct answer to your question. hope i , stop looking at this easily, look at it with a spectral view.

step-by-step explanation:

told you