In a certain board game a 12 sided number cube showing numbers 1-12 is rolled. If 3 such number cubes are rolled, what is the probability that at least 1 show as a 2?

This question is based on the probability. Therefore, the probability that at least 1 show as a 2 is 0.22974 if 3 such number cubes are rolled.

Given:

In a certain board game a 12 sided number cube showing numbers 1-12 is rolled.

We need to determined the probability that at least 1 show as a 2, if 3 such number cubes are rolled.

It is given that total faces of = 12 labeled 1 - 12

Now calculating probability of showing a two ;

Hence, probability of not showing a 2 is,

Now, calculating probability that at least one of 3 cubes shows as a 2 =

1 - P(none of the cubes shows a 2)

Probability that at least one of 3 cubes shows as a 2 = 1 - 0.770 = 0.22974

Therefore, the probability that at least 1 show as a 2 is 0.22974 if 3 such number cubes are rolled.

For more details, prefer this link:

link

0.2297453

Step-by-step explanation:

Given that :

Total faces of = 12 labeled 1 - 12

Probability of showing a 2 ;

P = required outcome / Total possible outcomes

P(showing a 2) = 1 /12

Hence, probability of not showing a 2 ;

P(showing a 2)' = 1 - 1/2 = 11/12

Probability that atleast one of 3 cubes shows a 2 :

1 - P(none of the cubes shows a 2)

P(none of the cubes shows a 2) =

(11/12 * 11/12 * 11/12) = 0.7702546

1 - 0.7702546 = 0.2297453

step-by-step explanation:

we are given

since, we have to isolate x on anyone side

so, we can move all x terms on one side

subtract both sides by 2x

add both sides by 9

divide both sides by 4

we get