Visit lives 5km from the school. She walks 1km at 4km/h and travels the rest of the way by bus at 16km/h. What is the average speed for the whole journey

0.63km/h

Step-by-step explanation:

Step one:

given data

total distance= 5km

velocity of walk= 4km/h

distance covered while walking= 1km

time taken to walk

t1= 4/1

t1= 4hours

Step two:

velocity of bus= 16km/h

distance covered while walking= 5-1= 4km

time taken to walk

t2= 16/4

t2= 4hours

total time = 4+4=8hours

Average speed= total distance/total time taken

average speed= 5/8

average speed=0.63km/h

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )