The weights of 1500 ball bearings are normally distributed with a mean of 22.40 oz and a standard deviation of 0.048 oz. If 300 random samples of size 36 are drawn from this population, determine the expected mean and standard deviation of the sampling distribution of means if sampling is done (a) with replacement, (b) without replacement. Solve Problem 5.51 if the population consists of 72 ball bearings.

Step-by-step explanation:

Given that:

The mean = 22.40

The standard deviation = 0.048

Sample size n = 36

Then; the expected mean = = 22.40

With Replacement;

The standard deviation

Without replacement;

The standard deviation

Also;

For population consisting of 72 ball bearings.

the expected mean = = 22.40

With Replacement;

The standard deviation

Without replacement;

The standard deviation

its 60

4 x 12 = 48

3 x 4 = 12

48 + 12 = 60

yeeeet

32

step-by-step explanation: