Given SD HT; SH=ST prove SHD= STD

The proof of is given below.

Given, SD is perpendicular to HT.

We have to prove .

Now, In ,

( since SD perpendicular to HT, so both will be 90 ).

( given in question ).

( common side in both the triangle ).

So, by Right angle hypotenuse congruence rule,

.

Hence the proved above.

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Δ SHD ≅ Δ STD (By SAS)

Step-by-step explanation:

Given:

SD⊥HT

SH=ST

Prove:

Δ SHD ≅ Δ STD

Computation:

SH=ST (Given)

SD = SD (Common)

∠SHD = ∠SDT (right angle) (SD⊥HT)

So,

Δ SHD ≅ Δ STD (By SAS)

since proposition states that a number is greater than 25, if is true then the number must actually be greater than 25.

this implies that all possible options, except 24, can be accepted