PLEASE HELP HEHE A bag contains 3 red balls, 8 blue balls and 11 white balls. What is the probability of drawing two balls after replacing the first ball; first is red and then a white ball? Round to the nearest tenth and include a percent sign

Step-by-step explanation:

Probability = expected outcome/total outcome

If a bag contains 3 red balls, 8 blue balls and 11 white balls, then the total outcome will be;

Total outcome = 3 + 8 + 11 = 22 balls

Since we are drawing two balls with replacement;

Probability of drawing red ball = number of red/total outcome = 3/22

Probability of drawing white ball = number of while/total outcome = 11/22 = 1/2

Probability of drawing red first and then white = 3/22 * 1/2

Probability of drawing red first and then white  = 3/44

To the nearest tenth, 3/44= 0.1

In percent = 6.8%

y = - 6

step-by-step explanation:

given the point (- 2, y) lies on the graph then it is a solution of it's equation.

substitute x = - 2 into the equation for value of y

y = 3(- 2) = 3 × - 2 = - 6

the point on the graph is (- 2, 6)

its d. the first coordintaes are 10,32

step-by-step explanation: