What is the magnitude and direction of -(3.7+7.4)?

Complete question is;

What is the magnitude and direction of (-3.7i) + (7.4j)?

Magnitude = 8.27

Direction = 116.57°

Step-by-step explanation:

Magnitude of the vector will be;

|R| = √((-3.7²) + (7.4²))

|R| = √68.45

|R| = 8.27

Direction will be;

tan θ = 7.4/-3.7

tan θ = -2

θ = tan^(-1) -2

θ = -63.43°

Angle is negative but we can't present it as such.

Now, in the second and fourth quadrants, tan θ has a negative value.

However, from the components of the vector we are given, we see that we work here in the 2nd quadrant since the i vector is negative and j vector is positive. Therefore, a reference angle of 63.43° means that the actual angle is 63.43° above the negative x axis and can be written in standard form as;

180 − 63.43 = 116.57°

$25

step-by-step explanation:

25 - 4.50 = 20.5

20.5 / 2 = 10.25

10.25 + 10 = 20.25

20.25 - 12.50 = 7.75

therefore the answer is $25 as shown as the first number.