What is an equation of the line that passes through the points (3,4) and (5,8)

Step-by-step explanation:

In the equation y=mx+b, 'm' is the slope of the line and 'b' is the y-intercept.  

First, you should find the slope of the line.  To do this, use the equation M=y2-y1/x2-x1.  Using the two given points (3,6) and (8,4), you can solve for M.  

M=4-6/8-3

M=-2/5 (-0.4 in decimal form)

Now, your equation is y=-0.4x+b

Next you must solve for b to find the y-intercept.  You can do this by subbing one of the given points in for x and y.  

Using the point (3,6):

y=-0.4x+b

6=-0.4(3)+b

6=-1.2+b

Isolate b:

6+1.2=b

b=7.2

And now you have the equation of the line!

y=-0.4x+7.2 (IN FRACTION FORM: y=-2/5x+36/5)

i dont understand the question? ?

step-by-step explanation:

the answer is:

the correct option:

b.

to solve the problem, we need to remember how to operate to simplify exponential expressions using the logarithms.

we are given the equation:

then, using placing logarith with base 7 on both sides of the equation, we have:

so, rounding the obtained result to two decimal places (nearest hundreth), we have:

hence, we have that the correct option:

b.

have a nice day!