The graph represents a system of linear equations comparing the outside and inside temperatures y, in degrees Fahrenheit, recorded at a school one day x hours after 8:00 a. m. A coordinate grid showing Daily Temperature with Hours after 8:00 a m on the horizontal, x axis and Temperature in degrees Fahrenheit on the vertical, y, axis. One line labeled Inside passes through (0, 70) and (8, 70). The second line passes through (0, 58) and passes through (8, 70).
After how many hours were the inside and outside temperatures equal?

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."

never fear papaguy is here

answer

hello 0xxbadwolfxx0,

2.6 x 10^9 is 2,600,000,000.

1.3 x 10^2 is 130

multiplying 130 and 2,600,000,000 would simply give you 200,000,000,000.

therefore, the answer would be d. 2.0 × 10^11.

i hope i ! warm regards, mae.