4 consecutive integers have a sum of 22. What is the least of the 4 integers?

The least of the four integers is 4.

Step-by-step explanation:

Let x be the first integer.

x + (x + 1) + (x +2) + (x + 3) = 22

4x + 6 = 22

4x = 16

x = 4

4 + 5 + 6 + 7 = 22

answer: 94

step-by-step explanation: 79+91+92+94+94 = 450 divided by 5 (since there are 5 number that are being added) = 90

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