Given: QS bisects ∠TQR; TQ ≅ RQ. Prove: ΔQRS ≅ ΔQTS Triangles Q T S and Q R S are connected at side Q S. Line Q S bisects angle T Q R. The lengths of sides Q T and Q R are congruent. Complete the missing parts of the paragraph proof. Proof: We know that segment QS bisects angle TQR because . By the definition of angle bisector, angle TQS is congruent to angle . We see that segment QS is congruent to segment SQ by . Therefore, we can conclude that triangles QRS and QTS are congruent by .

We know that segment QS bisects angle TQR because IT IS A GIVEN. By the definition of angle bisector, angle TQS is congruent to angle RQS. We see that segment QS is congruent to segment SQ by the REFLEXIVE PROPERTY. Therefore, we can conclude that triangles QRS and QTS are congruent by SAS.

Step-by-step explanation:

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it is given, RQS, the reflexive property, and SAS

Step-by-step explanation: just did it

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y = 2x

step-by-step explanation:

if you divide each number in the sequence, you'll see that they all have a multiple factor of 2. each number in the series, and any other numbers which may continue, will be multiplied by 2. therefore, y is the next number in the sequence, and x is the current one, so, our formula will be y = 2x.