The difference of two numbers is 19. The larger number is 8 less than 4 times the smaller number. Find the two numbers.

let the larger number be x and smaller number be y

1 equation

x-y=19

or x=19+y

2 equation

x=4y-8

then

putting valu of x in eqn 2nd

19+y=4y-8

19+8=4y-y

27=3y

y=9

so putting value of y in eqn 1

x= 19+9

 x=28

therfore, larger number =28

smaller number =9

Step-by-step explanation:

yess

step-by-step explanation:

idk whyy this is happening, i cant even read my notification bc i keep getting errors

~coco

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.