In ΔEFG, \overline{EG} EG is extended through point G to point H, \text{m}\angle EFG = (2x+1)^{\circ}m∠EFG=(2x+1) ∘ , \text{m}\angle FGH = (6x+2)^{\circ}m∠FGH=(6x+2) ∘ , and \text{m}\angle GEF = (x+19)^{\circ}m∠GEF=(x+19) ∘ . Find \text{m}\angle GEF. m∠GEF.

the answer is: d) o, f, and kr.

atomic radius of bromine (br) is 114 pm.

atomic radius of oxygen (o) is 73 pm.

atomic radius of fluorine (f) is 72 pm.

atomic radius of krypron (kr) is 112 pm.

the atomic radius of a chemical element is a measure of the size of its atom.

the atomic radius varies with increasing atomic number, but usually increases because of increasing of number of electrons.

the atomic radius decreases across the periods because an increasing number of protons, because greater attraction between the protons and electrons.

jml angle lkj & angle mj = lm

the answer would be a 24

step-by-step explanation:

c=2πr=2·π·3=24

step-by-step explanation: