A kid traveled a distance of 9 km by bike, and then walked a distance of km. a. Find the total distance traveled in terms of
b. If the total distance was less than 30 km, form an inequality in , and
then solve it!

Step-by-step explanation:

The question is incomplete. Here is the complete question;

A kid traveled a distance of 9 km by bike, and then walked a distance of x km.

a.Find the total distance traveled in terms of  x

b. If the total distance was less than 30 km, form an inequality in x, and

then solve it!

a) Total distance = distance travelled by bike + distance walked

Total distance = 9km + xkm

Total distance = (9+x)km

b)  If the total distance was less than 30 km, the inequality representing this is;

9+x < 30

Subtract 9 from both sides;

9+x-9 < 30-9

x < 21

hence the solution to the inequality is x< 21

a framing bias

step-by-step explanation:

rodrigo is subject to a framing bias i believe.

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3