What is the equation of the line, in general form, that passes through the point (1, 1) and has a y-Intercept of 2
Ox+y20
Ox-y + 20
OX-y-20

y = -x + 2

Step-by-step explanation:

The equation of line is often written in the form;

     y = mx + c

y and x are the coordinates

m is the slope

c is the intercept

 From the given parameters;

        c  = 2

     (1,1) are the coordinates

Let us find the slope of the line;

      1  = m(1) + 2

       1  = m + 2

          m = 1- 2  = -1

The equation of the line is;

         y  = -1x + 2

         y = -x + 2

x > 1.3

step by step:

8.5−0.9x> 9.8−1.9x

step 1: simplify both sides of the inequality.

−0.9x+8.5> −1.9x+9.8

step 2: add 1.9x to both sides.

−0.9x+8.5+1.9x> −1.9x+9.8+1.9x

1x+8.5> 9.8

step 3: subtract 8.5 from both sides.

1x+8.5−8.5> 9.8−8.5

1x> 1.3

step 4: divide both sides by 1.

1x/1 > 1.3/1

linear pair postulates