Find the slope, if it exists, of the line containing the pair of points. (−13,−6) and (−18,−9)

Step-by-step explanation:

-9--6=-3

-18--13=-5

-3/5

y = 3x+4

step-by-step explanation:

to find the slope

slope = (y2-y1)/ (x2-x1)

    = (-8-4)/ (-4-0)

    = -12/-4

  = 3

using the slope intercept form of a line

y= mx+b

we know the slope is 3

we know the y intercept is 4 ( the point where it crosses the y axis or x=0)

y = 3x+4

could u provide us some answer choices or hmm idk maybe a table for us to anser with ? ?