Find the slope and y-intercept from the following graph of a linear equation.

For this question, you need to find the slope-intercept form of the graph. To do this, start with two points and plug them into y2-y1 / x2-x1.

(-1,-1)(1,7)

7 - - 1 / 1 - - 1 = 8/2 = 4

Therfore, your slope is 4

Next, the y-intercept. This is the point where the graph crosses with the y. In this problem, the lines intercept at the point (0,3).

Therefore, your y-intercept is 3

Y-intercept = 3, Slope = 4

Slope-Intercept form is y = 4x + 3

step-by-step explanation:

through just a quick inspection, one can see that the graph of this cubing function starts in quadrant iii and ends in quadrant i.   when x = 0, y = 3, so the y-intercept is (0, 3).

if graphs are part of the problem statement, share them.   .

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step-by-step explanation: