A ship moves through water at 30miles/hour at an angle of 30 south of east. the water is moving 5miles/hour at an angle of 20 east of north. identity the ships vector, the water currents vector, and the vector representing the ships actual motion

answer: i literally just answered this question but they want me to do it again

step-by-step explanation:

answer: cos [   arcsin (3/5) - arccos (1/2) ] =

step-by-step explanation: × = 3/5 = 0.6--> x = 36.87 and x = 180 - 36.87 = 143.13 deg

cos y = 1/2 --> y = +- 60 deg a. cos (x - y) = cos (143.13 - 60) = cos 83,13  

=

0.12

b. cos (36.87 - 60) = cos (-23.23) = 0.92

20days louise can read300 pg

step-by-step explanation:

1 day 15 pg 300: 15= 20

x day 300 pg

30,40,50 is correct answer